easy veasy
Level
pending
A two-digit number is 1 more than nine times the sum of its digits. Which number is it?
The answer is 91.
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Suppose the numb is ab Then ab=10a+b The term is ab=9(a+b)+1 10a+b=9a+9b+1 a-8b=1 Only one solution a=9 & b=1 because a,b=0,1,...,9 So the numb is 91