ECHO...ECHo...ECho...Echo...echo...

The distance for the sound to travel is $(6km)(2)=12km=12000m$ . The echo would take $\frac{12000m}{350\frac{m}{s}}=\boxed{34.29}$ seconds.

At the narrowest point the distance that the sound has to travel is equal to 12KM because the sound has to return. Thus, we can calculate the amount of seconds that sound has to travel for as 12000m*1s/350m=34.290s

Narrowest point = 6 km.

For echo to reach other end and come back to you, total distance travelled by sound = 6km x 2 = 12 km

Time taken for echo to reach back to you = 12000m (distance travelled)/ 350m/s (speed of sound) = 34.29s (to 4sf)

velocity(v)=displacement(s)/time(t)

By rearranging we get,

t = s/v

(Putting in values)

s = 12 km (counting both ways) = 12,000m

v = 350m/s (given)

t =6 2 1000/350=34.29

(6000*2)/350=34.285

The distance for the sound to travel is (6km)(2)=12km=12000m. The echo would take 12000m350ms=34.29 seconds.

for this problem, the narrowest point would be 6 km or 6,000 m, the speed of sound is roughly 350 m/s

so we can use the formula t = $\frac {s}{v}$

thus we will obtain t = $\frac {6000}{350}$

that is equal to 17.142857 and so on but it is the time for the sound to reach the end of 6km cliff , so to obtain the total time until we hear the echo

$17.142857 \times 2$ = 34.285714

and by using decimal approach we will obtain $\boxed {34.3}$

• As we are standing at the narrowest point therefore, the distance that we have to take is 6 Km.
• Now,the distance to be travelled by the sound is = $2 \times 6000$ m.
• Hence the net Time = 12000/350 sec. = 34.3 sec

You stood at its narrowest point, therefore, you are 6 km in distance. You shouted, the sound will travel to the place, and then bounce back to your ears so you can hear the echo. Therefore, it travels 12 km, or 12000meters. From the details above, you can see that the speed of sound is considerably 350 m/s. And we know that s = v.t Where s = the distance travelled by the sound which is 12000m and v is the velocity of the sound, which is 350 m/s, so by putting these quantity in the above equations, the time taken would be 34.290 s

The question says the we are on a side of a narrowest point, so the other end would be 6 KM away. My echo would have to travel 6+6=12 KM(the sound wave has to go and return also). So, the distance is 12,000 Meters and speed is 350 m/s. Therefore, Time taken= 12000/350 = 34.285 seconds

Total distance travelled is twice the diameter, therefore 6km x 2

Divided by the speed of sound 350, which is (12000(m)/350(m/s)) = 34.2857... s.

Easy, The narrowest corner is 6KMs. The sound needs to travel 6 2 (upstream & downstream) = 12 KMs...speed of sound is 350m/s...hence the solution is 12 1000/350 = 34.290