Eggs and Meteorite

A farmer is on the way to market to sell eggs when a meteorite hits his truck and destroys all of his produce.

In order to file an insurance claim, he needs to know how many eggs were broken.

He knows that when he counted the eggs by 2's, there was 1 left over;
when he counted them by 3's, there was 1 left over;
when he counted them by 4's, there was 1 left over;
when he counted them by 5's, there was 1 left over;
when he counted them by 6's, there was 1 left over;
but when he counted them by 7's, there were none left over.

What is the smallest number of eggs that were in the truck?


The answer is 301.

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2 solutions

Venkatachalam J
May 8, 2017

LCM of (2,3,4,5,6)=60

The required number is (60.x +1)%7=0.

x=5, which is the minimum value satisfying the above equation 301%7=0.

So the required result is 301.

Because we have 1 left by dividing by 2 is has to be an odd number of eggs. Next to that it has to be divisible by 7 and give 1 left by dividing by 5. So it has to be a number which is a 1 mod 10. Looking at the table of multiplication of 7 we see that this only happens when 7 is multiplied by 3. So what's left now is finding a multiple of 7 which is 3 mod 10 and which satisfies the other requirements. This is 43(it is the first number which satisfy 1 mod 3,4,6), so the answer is 7 x 43 = 301.

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