Egyptian fraction? What's that?

The Egyptian fraction of 5 7 \frac 57 can be expressed as 1 a + 1 b + 1 c \frac 1a + \frac 1b + \frac 1c

Evaluate the maximum value of a + b + c a+b+c

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The answer is 77.

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1 solution

Relevant wiki: Egyptian Fractions .

The greatest fraction of form 1 p < 5 7 \dfrac 1p < \dfrac 57 is 1 2 . \dfrac 12.

We substract 5 7 1 2 = 3 14 . \dfrac 57 - \dfrac 12 = \dfrac {3}{14}.

The greatest fraction of form 1 p < 3 14 \dfrac 1p < \dfrac {3}{14} is 1 5 . \dfrac 15 .

We substract 3 14 1 5 = 1 70 . \dfrac {3}{14} - \dfrac 15 = \dfrac {1}{70} .

Therefore, 5 7 = 1 a + 1 b + 1 c = 1 2 + 1 5 + 1 70 . \dfrac 57 = \dfrac 1a + \dfrac 1b + \dfrac 1c = \dfrac 12 + \dfrac 15 + \dfrac {1}{70} .

Hence, a + b + c = 2 + 5 + 70 = 77 . \boxed{a + b + c = 2 + 5 + 70 = {\color{#20A900}{77}}} .

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