Time Dilation In Airplanes?
An atomic clock in an airplane measures a time interval of an hour when the jet moves with speed .
During this time, an identical clock is held by an observer at rest on the ground. What is the increase (in nanoseconds) of the time measured?
The answer is 3.2.
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1 solution
The factor of time dilatation relative to the time past in the moved system is given by:
γ = 1 − c 2 v 2 1
v is the speed of the jet and c denotes velocity of light. We get γ = 1 . 0 0 0 0 0 0 0 0 0 0 0 0 8 9 and multiplied with 3600 seconds a time inteval of 3600.00000000320 seconds for the observer on the ground. That means the interval is 3.2 nanoseconds longer compared to the jet's one!
The time runs faster on the ground and therefore someone ages faster in the silent reference system whereat the efficieny of the effect is only significant for velocities nearby that of light!
For this please see twins' phenomenon.