Three charged particles are placed in such a way that one of the particles is the midpoint of a line segment connecting the other two. If the particles at the ends of the line segment have charge , then what should the the charge of the third particle be so that the system is in equilibrium?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Let us place the two + Q charges on the x − axis at ( − r , 0 ) and ( r , 0 ) . If the third charge is positive, then it will repel when placed at the midpoint ( 0 , 0 ) of the aforementioned positive Q-charges. It must be negatively charged to allow equilibrium in this system (call it − q ) . By Coulomb's Law ( F = d 2 k q 1 q 2 ), the attractive force between Q , − q must equal the repulsive force between Q , Q . We require:
( 2 r ) 2 k Q 2 = − r 2 k Q q ⇒ q = − 4 Q .