Electric circuit.

first try to draw another circuit like this but in a simple form.then it will be very easy to be solved.let's see the calculation. calculation: 1st 2 resistance is connected in parallel combination. 1/Cp1 =1/2+1/2 Cp1=1 ohm last 2 resistance is also connected in a parallel combination. Cp2=1 ohm again this Cp1&Cp2 is connected with each other in a series combination. Cs1=1+1 =2 ohm this Cs1 is connected with 3rd resistance in a parallel combination. so 1/ Cp=1/Cs1+1/2 =1/2+1/2 Cp=1 ohm here Cp is the equivalent resistance of the circuit . so answer 1 ohm

first two and last two resistance are in parallel and equivalent of these combination are in series with each other(1 ohm & 1 ohm).which is in parallel with middle resistance of 2 ohm. so the equivalent resistance is =(2*2)/(2+2)= 1 ohm