Electric Energy
A household electric power outlet (assume 220 V constant voltage) is fused to cut at if the current equals or exceeds 20 Ampere. A 2 kW heater, 1kW Air conditioner and three 100 W bulbs are already running at rated power. If now somebody wants to run a computer then computer can run without causing fuse to burn if power requirement of computer is (neglect losses in current carrying wire).
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1 solution
In a circuit, the powers of the appliances always add up. Let the power of the computer be x W. Therefore, the total power in the circuit is equal to
P T o t a l = 2 0 0 0 + 1 0 0 0 + 3 ∗ 1 0 0 + x .
ie. P T o t a l = ( 3 3 0 0 + x ) W .
P o w e r = I ∗ V . Hence, I = ( 3 3 0 0 + X ) / 2 2 0 .
But I ≤ 2 0 A .
Hence I ≤ 1 1 0 0 .
Therefore, A B C is the correct option.