Electric field lines

The above diagram shows the lines of electric force and equipotential lines on a particular plane. Which of the following statements is correct?

a) The electric potential at point A is higher than that at point B .
b) The electric field strength at point A is the same as that at point B .
c) The work done by the electric force when an electrically charged particle is moved from point B to C along the equipotential line is zero.

a) only a) and c) a) and b) b) only

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4 solutions

Arti Chopra
May 31, 2018

The work done in moving a charge on a equipotential surface is always zero Hence if we move the charged particle from B to C the work done will be zero. According to the mathematical representation of electric field "V= Kq/r" As the distance (r) increases the electric potential (V) will fall down . Here point A is near than that of the point B, so the potential at point A will be higher than that of B.

Shahbaz Khan
Apr 6, 2014

we know V1 -V2 =W12/q so equipotential surface have V1=V2 so 0=w/q , w=0 ...... and F=Kq2/r2 so move A to B "r " increses then F decrese

ZainRehman Ansari
Nov 28, 2018

A & C are the Right Answer Because Point A is near the centre than point B So The electric potential at point A is higher than that at point B. According to the mathematical Formula of electric field "V= Kq/r" As the distance (r) increases the electric potential (V) will fall down.Here point A is near than that of the point B, so the potential at point A will be higher than that of B.

Mir Jahan
Apr 5, 2014

work is done when a charged is moved between two points where potential difference exists. When charge is moved between two potential points then work done is zero

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