Electric Flux 8-23-2020

A circular ring has uniform linear charge density σ = + 1 \sigma = +1 . The ring is parametrized as follows:

x = ( 3 / 5 ) cos α y = ( 3 / 5 ) sin α 0 α 2 π z = 1 2 x = (3/5) \cos \alpha \\ y = (3/5) \sin \alpha \\ 0 \leq \alpha \leq 2 \pi \\ z = \frac{1}{2}

What is the electric flux through a sphere of radius 1 1 with its center at the origin?

Details and Assumptions:
1) Use outward-facing normal vectors for the sphere
2) Electric permittivity ϵ 0 = 1 \epsilon_0 = 1


The answer is 3.77.

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1 solution

Talulah Riley
Aug 23, 2020

Gauss law states that no matter where the charge is placed inside the 3D objects, The total flux will be ϕ = q i n s i d e ϵ 0 \phi=\frac{q_{inside}}{\epsilon_{0}} ϕ 3.7699 \boxed{\phi \approx 3.7699}

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