Electric potential between 2 charged plates

Electricity and Magnetism Level 1

A uniform electric field is formed between two charged plates as shown above. The electric field strength is 0.2 N/C 0.2 \text{ N/C} . If the distance between the two points A and B is 0.5 m 0.5 \text{ m} , then what is the electric potential difference between A and B ?

0.3 V 0.5 V 0.1 V 0.2 V

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Lakshan Dumpa by Lakshan Dumpa , 24, India

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3 solutions

Δ \Delta V = E × \times Δ \Delta d

V a − V b = E × d a − d b V_a - V_b = E \times d_a - d_b

Δ V = 0.2 N C × 0.5 m = 0.1 V \Delta V = 0.2 \frac{N}{C} \times 0.5m = 0.1V

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Mohamed Samer
Sep 11, 2014

V is alwys the larger I just multiplied them.:-D

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Abhishek Rawat
May 22, 2014

we know that , E=V/D given:E=0.2 N/C & D=0.5 m hence V=E D=0.2 0.5=0.1V

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