Electric resistance

Electricity and Magnetism Level 1

What is the total resistance and current intensity flowing into the ampere meter of the above circuit?

6.0 Ω , 4.00 A 6.0 \ \Omega, 4.00 \text{ A} 13.0 Ω , 1.85 A 13.0 \ \Omega,1.85 \text{ A} 7.0 Ω , 3.43 A 7.0 \ \Omega, 3.43 \text{ A} 10.0 Ω , 2.40 A 10.0 \ \Omega, 2.40 \text{ A}

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Lakshan Dumpa by Lakshan Dumpa , 24, India

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3 solutions

Alpesh K
Jul 26, 2014

R(Resistance)= 4+1/3+1/6=6 now I(current)=Voltage/Resistance= 24/6=4

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Ankit Vijay
Jun 12, 2014

electricity rocks Great question tho..

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Yash Maurya
Jun 10, 2014

By parallel combination the effective resistance of 3 & 6 is 2 ohms which is in series with the 4 ohm resistance which gives the total effective resistance of 6 ohms....then by using Ohm's Law the current will be I equal to V/R i.e. 4 A

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How does the resistance in parallel come to 2 ohms?

Siddharth Mehta - 6 years, 12 months ago

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1 R e q = 1 R 1 + 1 R 2 \frac{1}{R_eq}=\frac{1}{R_1}+\frac{1}{R_2}

Bernardo Sulzbach - 6 years, 11 months ago

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