Electric SHM!

A particle of mass m m and charge Q Q is placed in an electric field which varies with time according to the relation E = E 0 s i n ω t E = E_0 sin\omega t . Neglecting all energy losses due to acceleration of a charge, the amplitude of SHM that the particle will undergo if it starts from rest is :

Q E 0 m ω 2 \frac{QE_0}{m\omega^2} None of these 2 Q E 0 m ω 2 \frac{2QE_0}{m\omega^2} Q E 0 2 m ω 2 \frac{QE_0}{2m\omega^2}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...