Electricity And Magnitism, Resistance

$For\quad x\quad number\quad of\quad resistors\quad of\quad resistance\quad 176Ω\quad ,\quad the\quad equivalent\quad \\ resistance\quad of\quad the\quad resistors\quad connected\quad in\quad parallel\quad is\quad given\quad by\quad \\ Ohm’s\quad law\quad as\\ \\ V=IR\\ \\ I=\frac { V }{ R } \\ \\ Supply\quad voltage\quad ,V=220V\quad \\ \\ Current,I=5A\\ \\ Equivalent\quad resistance\quad of\quad the\quad combination=R,\quad given\quad as\\ \\ \frac { 1 }{ R } =x\quad \times \frac { 1 }{ 176 } \\ \\ R=\frac { 176 }{ x } \\ \\ x=\frac { 176\times I }{ V } \\ \\ x=\frac { 176\times 5 }{ 220 } \\ \\ x=\quad 4$

V=IR 220= 5×R R=44 In parallel combination of resistors 1/R= reciprocal of sum of all individual resistors 1/44 = N/176 ( where "N" is the number of resistors) N= 4

for effective resistance in parallel, R/n, V=IR/n, find n, substituting V=220, I=5, R=176....n=4

Ohm's Law gives us

V=IR; R=V/I; R=220V/5A = 44 Ohms;

For resistors of equal value Equivalent resistance 1/R=y(1/176) [for parallel connection 1/R=1/R1+1/R2+....1/Rn]; 1/44=y/176; or, 176/y=44; or, y=176/44; So, y=4

V=IR i.e R=V/I here total resistance in the circuit is R where V=220 and I=5A. So R=220/5=44

Total resistance is 44 ohm. In a parallel Circuit R(total)=1/(1/R1+1/R2+...+1/Rn) Here, one resistor value is 176 ohm

So denominator of the equation is always equal..

therefore 44ohm=176ohm/x simple algebraic equation where x=176/44= 4..the total number of resistors

Since V = IR

I = V/R

I = 220/176 = 1.25 A

this is 1/4 of 5 A thus 4 resistors required.