Electricity And Magnitism, Resistance

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor?

0.660 A 0.660A 0.669 A 0.669A 0.671 A 0.671A 0.675 A 0.675A

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Tammu Triveni
Jun 15, 2014

since they are in series total resistance is 0.2+0.3+0.5+0.4+12=13.4 current=V/R=9/13.4= 0.671 A. same current flows through all the resistors in series connection. hence, current in 12 ohm resistor=0.671A

Ankit Vijay
Jun 3, 2014

I have already submitted the solution here https://brilliant.org/community-problem/electricity-and-magnitism-resistance-13/?group=TTyIC6PjADts

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...