Electricity And Magnitism, Resistance

Several electric bulbs designed to be used on a 220 V electric supply line, are rated 10 W. How many lamps can be connected in parallel with each other across the two wires of 220 V line if the maximum allowable current is 5 A?

110 100 88 112

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2 solutions

Caleb Townsend
Feb 8, 2015

We know that P = I V . P = IV. The power of the supply line is n × 10 W b u l b n\times 10 \frac{W}{bulb} , where n n is the number of electric bulbs on the supply line. Substituting P = n × 10 W b u l b P = n\times 10 \frac{W}{bulb} into P = I V P = IV and solving for n n gives n = I V 10 b u l b s W n = \frac{IV}{10}\frac{bulbs}{W} Now, substituting the given values V = 220 V V = 220 V and I = 5 A I = 5 A yields n = 1100 W 10 b u l b s W = 110 b u l b s n = \frac{1100 W}{10}\frac{bulbs}{W} = \boxed{110\ bulbs}

Uday Kumar
Jun 10, 2014

From ohms law we have I=V/R i.e R=V/I R=220/5 R=110

220/5 is not equal to 110 though...

Caleb Townsend - 6 years, 4 months ago

This is wrong people It should 44and I answered 88 I knew it was wrong Please be advice

Laith Hameed - 6 years, 12 months ago

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