A copper wire has diameter 0.5 mm and resistivity of 1.6 × 10−8 Ω m. What will be the length of this wire to make its resistance 10 Ω? How much does the resistance change if the diameter is doubled?
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No need to do the complex calculations for the length of the wire. It is easier to solve the second part. The diameter has an inverse square relationship with the resistance. If the diameter is doubled, the resistance will become one-fourth and one-fourth of 10 is 2.5. Only one option contains this value so it is the right answer.