Electrified

The charges with magnitude q q are held fixed in place by external unspecified forces. The charges with magnitude Q Q are free to move.

If the system is in equilibrium, find Q q \dfrac{Q}{q} to 2 decimal places.


The answer is 2.82.

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1 solution

Erasmo Hinojosa
Apr 30, 2016

Such a system where all of the four charges are in equilibrium is impossible. Invesitgating the forces on either of the Q + Q^+ yields the ratio: Q q = 2 2 \frac {Q} {q}= 2 \sqrt{2} . But, while equilibrating the forces on either q q^- charge rapidly yields: Q q = 1 2 2 \frac {Q} {q}=\frac {1} {2 \sqrt {2}} which is contradictory with what we found before. This is due to the fact that any charge feels the same force along the square side, directly towards the charge on the adjacent vertex but if Q q Q \neq q the force that the charges feel in the diagonal direction, directly away from the charge from the opposite vertex will never be same, hence is impossible to balance the system. If those forces were meant to be the same would meant that all the charges should have the same magnitude and, consequently, the forces that they would feel to the sides would be greater than thhose in the diagonal direction and, again, the forces won't balance. P.D. I entered my solution as: Q q = 2 2 \frac {Q} {q}= 2 \sqrt{2}

Nice work!

Swapnil Das - 5 years, 1 month ago

But the question is fine, if it mentions an unspecified force that keeps the charges q q at rest, right?

A Former Brilliant Member - 5 years, 1 month ago

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Yes, its true, but it is really important it exists another force that keeps the system in equillibrium but, the most importat, be specific by stating on whic forces does this force acts.

Erasmo Hinojosa - 5 years, 1 month ago

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I completely agree.

A Former Brilliant Member - 5 years, 1 month ago

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