electrified!!!
Electricity and Magnetism
Level
2
A particle of charge 5C moves perpendicularly to magnetic field of magnitude 0.01T. If the velocity of the charge is 1.5m/s, calculate the magnitude of the force exerted on the particle?
The answer is 0.075.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
Force on a moving charge is: qvB sin theta, where theta is angle between velocity and mag. field vectors. Here it is 90 and hence sin theta = 1. F is simply 5 * 0.01 * 1.5