Electrochemistry-Level 2
Chemistry
Level
2
For
assumption and details
, please refer my note from my set
Chemistry Challenge
.
The answer is 1.21.
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1 solution
Well obviously we are supposed to find the reduction potential of C a ∣ ∣ A l . Now, E A l ∣ ∣ K = E A l ∣ ∣ L i + E L i ∣ ∣ K , which gives , E A l ∣ ∣ K = − 1 . 3 7 + 0 . 1 1 = − 1 . 2 6 Then, E K ∣ ∣ A l = − ( E A l ∣ ∣ K ) = 1 . 2 6 and, E C a ∣ ∣ K = − ( E K ∣ ∣ C a ) = − 0 . 0 5 Finally we get, E C a ∣ ∣ A l = E C a ∣ ∣ K + E K ∣ ∣ A l = − 0 . 0 5 + 1 . 2 6 = 1 . 2 1
PS: Even im not sure if my solution is ryt so comment if my approach is wrong ;)