Electrochemistry...#1

We have taken a saturated solution of $\text{AgBr}$ , whose $K_{sp}$ is $12 \times 10^{-14}$ . If $10^{-7}\text{ M}$ of $\text{AgNO}_{3}$ is added to 1 L of this solution, what would be the conductivity (specific conductance) of the solution?

Given, $\lambda^{o}_{(Ag ^{+})} = 6 \times 10^{-3} Sm^{2} mol^{-1}$ $\lambda^{o}_{(Br ^{-})} = 8 \times 10^{-3} Sm^{2} mol^{-1}$ $\lambda^{o}_{(NO_{3} ^{-})} = 7 \times 10^{-3} Sm^{2} mol^{-1}$

Express the answer in terms of $10^{-7} Sm^{-1} units$

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