Electromagnetic induction

The coefficient of self inductance of an inductor is 10 H \SI{10}{\henry} . The electric current through the inductor changes from 10 A \SI{10}{\ampere} to 7 A \SI{7}{\ampere} in 60 ms \SI{60}{\milli\second} . What is the average induced electromotive force (emf) across the inductor?

0 V 500 V 250 V 70 V 6 V 600 V 10 V 7 V

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1 solution

Steven Chase
May 6, 2017

V = L Δ i Δ t = 10 10 7 6 1 0 2 = 10 300 6 = 500 \large{V = L \frac{\Delta i}{\Delta t} = 10 \frac{10-7}{6 \cdot 10^{-2}} = 10 \frac{300}{6} = \boxed{500}}

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