The length of shadow of a pole of height 10m is 8m at a certain time -- then find out the height of the pole whose shadow is 32m long at that time.
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lets call the length of the shadow l , the angle of the sun from the earth x and the height of the pole h , then l h = t a n ( x ) . t a n ( x ) is constant at any given time so l h must also be constant therefore 8 1 0 = 3 2 h so 8 3 2 0 = h so h = 4 0 c m
Hey brett try out my problem on exponential growth
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I did, got the answer but typed it wrong :(
considering ∆ABC AB=10m BC=8m angleB=90' angle C=y'
similar to ∆DEF DE=x EF=32m angleE=90' angleC=y'
hence AB:BC =DE:EF
10:8=x:32
x=(10/8) 32
x=10X4
x=40m
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Consider this as the one of the easiest questions you have heard because you only need to solve a missing term in proportion ( This is an Elementary Technique )
8 : 10 = 32 : N
Considering the missing term is an extreme you will
1.) Multiply the MEANS ( Which are 10 and 32 )
2.) And then divide it by 8
3.) The result is automatically 40