Elementary School Math Problems-3

Geometry Level 1

The length of shadow of a pole of height 10m is 8m at a certain time -- then find out the height of the pole whose shadow is 32m long at that time.


The answer is 40.

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3 solutions

Consider this as the one of the easiest questions you have heard because you only need to solve a missing term in proportion ( This is an Elementary Technique )

8 : 10 = 32 : N

Considering the missing term is an extreme you will

1.) Multiply the MEANS ( Which are 10 and 32 )

2.) And then divide it by 8

3.) The result is automatically 40

Brett Hartley
Aug 30, 2014

lets call the length of the shadow l l , the angle of the sun from the earth x x and the height of the pole h h , then h l = t a n ( x ) \frac{h}{l}=tan(x) . t a n ( x ) tan(x) is constant at any given time so h l \frac{h}{l} must also be constant therefore 10 8 = h 32 \frac{10}{8}=\frac{h}{32} so 320 8 = h \frac{320}{8}=h so h = 40 c m h=\boxed{40cm}

Hey brett try out my problem on exponential growth

Aman Sharma - 6 years, 9 months ago

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I did, got the answer but typed it wrong :(

Brett Hartley - 6 years, 9 months ago

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Ohhh so sad

Aman Sharma - 6 years, 9 months ago
Jenosha Sarah
Oct 3, 2014

considering ∆ABC AB=10m BC=8m angleB=90' angle C=y'
similar to ∆DEF DE=x EF=32m angleE=90' angleC=y'
hence AB:BC =DE:EF
10:8=x:32
x=(10/8) 32
x=10X4
x=40m




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