Eletric field

A uniform electric field of 150 N/C downward exists near the surface of the Earth. Suppose an electron is “launched” from the end of a TV picture tube with a horizontal speed 2.0 × 1 0 7 2.0 \times 10^7 m/s and travels a horizontal distance of 20.0 cm before impacting the screen. Determine the acceleration of the electron due to the earth’s field.


The answer is 2.6E+13.

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2 solutions

Mayank Holmes
May 24, 2014

it's simple ............. you don't need to worry about horizontal velocity and all that!...........
Acceleration = ((charge on an electron ) * (electric field ) ) / (( mass of an electron))

Wonderful!!!!!! :)

Jayakumar Krishnan - 7 years ago

We know that a = F m = q E m a = \frac Fm = \frac{qE}{m} a = 1.6 × 1 0 19 × 150 9.1 × 1 0 31 a = \frac{1.6 \times 10^{-19}\times150}{9.1\times10^{-31}} a = 2.6 × 1 0 13 a = 2.6 \times 10^{13}

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