An ellipse is drawn with major and minor axes of lengths 10 and 8 respectively. Using one focus as the center, a circle is drawn that is tangent to the ellipse, with not part of the circle being outside the ellipse. Compute the radius of the circle.
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We've: x²/25+y²/16=1 and (x-3)²+y²=r². Solve for y in terms of r and set y=0 to obtain r² -10r +16 = 0 which gives r=2 or 8 of which the former is the admissible solution.