Embedded Polyhedron

Geometry Level 4

The centers of each face of a regular octahedron are used as vertices to draw a cube, and the centers of each face of the cube are used as vertices to draw a new octahedron.

Find the ratio of the volume of the bigger octahedron to the volume of the smaller octahedron.


The answer is 27.

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2 solutions

Jeremy Galvagni
Aug 15, 2018

Relevant wiki: Centroid of a Triangle

Here's a view looking straight at a vertex of the outer octahedron.

The cube touches the outer triangles at their centers which are 1/3 of the way in.

The sides of the inner octahedron are thus 1/3 as long as the outer one.

The outer octahedron has 3 3 = 27 3^{3}=\boxed{27} times the volume.

Nice visual! For everyone's benefit can you please explain why the centers of the outer triangles (that the cube touches) are 1/3 of the way in?

David Vreken - 2 years, 10 months ago

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Ok. Added Relevant Wiki.

Jeremy Galvagni - 2 years, 10 months ago
David Vreken
Sep 8, 2018

The radius of a circumscribed sphere of a octahedron with sides a a is r o c = 2 2 a r_{oc} = \frac{\sqrt{2}}{2}a and the radius of a inscribed sphere of a octahedron with sides a a is r o i = 6 6 a r_{oi} = \frac{\sqrt{6}}{6}a (see here ).

The radius of a circumscribed sphere of a cube with sides a a is r c c = 3 2 a r_{cc} = \frac{\sqrt{3}}{2}a and the radius of a inscribed sphere of a cube with sides a a is r c i = 1 2 a r_{ci} = \frac{1}{2}a (see here ).

If the smallest octahedron has a side r r , then the bigger octahedron has a side 2 2 2 1 3 2 6 6 r = 3 r \frac{\sqrt{2}}{2} \cdot \frac{2}{1} \cdot \frac{\sqrt{3}}{2} \cdot \frac{6}{\sqrt{6}}r = 3r . This makes the ratio of the sides of the bigger octahedron to the smaller octahedron 3 r r = 3 \frac{3r}{r} = 3 , so the ratio of volumes is 3 3 = 27 3^3 = \boxed{27} .

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