The centers of each face of a regular octahedron are used as vertices to draw a cube, and the centers of each face of the cube are used as vertices to draw a new octahedron.
Find the ratio of the volume of the bigger octahedron to the volume of the smaller octahedron.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Nice visual! For everyone's benefit can you please explain why the centers of the outer triangles (that the cube touches) are 1/3 of the way in?
The radius of a circumscribed sphere of a octahedron with sides a is r o c = 2 2 a and the radius of a inscribed sphere of a octahedron with sides a is r o i = 6 6 a (see here ).
The radius of a circumscribed sphere of a cube with sides a is r c c = 2 3 a and the radius of a inscribed sphere of a cube with sides a is r c i = 2 1 a (see here ).
If the smallest octahedron has a side r , then the bigger octahedron has a side 2 2 ⋅ 1 2 ⋅ 2 3 ⋅ 6 6 r = 3 r . This makes the ratio of the sides of the bigger octahedron to the smaller octahedron r 3 r = 3 , so the ratio of volumes is 3 3 = 2 7 .
Problem Loading...
Note Loading...
Set Loading...
Relevant wiki: Centroid of a Triangle
Here's a view looking straight at a vertex of the outer octahedron.
The cube touches the outer triangles at their centers which are 1/3 of the way in.
The sides of the inner octahedron are thus 1/3 as long as the outer one.
The outer octahedron has 3 3 = 2 7 times the volume.