Empirical Calculus

Calculus Level 3

A scientist has determined that an output quantity z z is related to input quantities x x and y y in the following way:

z = A x B y C \large{z = A \, x^B \, y^C}

Initially, the scientist's experimental setup has ( x 0 , y 0 , z 0 ) = ( 2 , 4 , 57344 ) (x_0,y_0,z_0) = (2,4,57344) . These are the experimental baseline numbers. The scientist then perturbs the inputs and measures the changes in the output in order to determine constants A , B , C A,B,C .

The results of the first trial are ( x = x 0 + 0.0001 , y = y 0 , z = z 0 + 8.6020301 ) (x = x_0 + 0.0001, y = y_0, z = z_0 + 8.6020301) .
The results of the second trial are ( x = x 0 , y = y 0 + 0.0001 , z = z 0 + 7.1683584 ) (x = x_0, y = y_0 + 0.0001 , z = z_0 + 7.1683584) .

Based on the scientist's empirical results, calculate A , B , C A,B,C and round each one to the nearest integer. Enter your answer as the sum of the three rounded numbers.


The answer is 15.

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1 solution

Steven Chase
Mar 18, 2018

By altering one variable at a time and comparing the change in the output to the change in the input, the scientist is effectively taking partial derivatives.

z = A x B y C z x = B A x B 1 y C = B A x B x 1 y C = B z x 1 B = z x x z z y = C A x B y C 1 = C A x B y C y 1 = C z y 1 C = z y y z \large{z = A \, x^B \, y^C \\ \frac{\partial{z}}{\partial{x}} = B A \, x^{B-1} \, y^C = B A \, x^B \, x^{-1} \, y^C = B \, z \, x^{-1} \\ B = \frac{\partial{z}}{\partial{x}} \, \frac{x}{z} \\ \frac{\partial{z}}{\partial{y}} = C A \, x^B \, y^{C-1} = C A \, x^B \, y^C \, y^{-1} = C \, z \, y^{-1} \\ C = \frac{\partial{z}}{\partial{y}} \, \frac{y}{z}}

Evaluate the expressions for B B and C C given measurement data. Then calculate A A using the baseline numbers. The results come out to:

A = 7 B = 3 C = 5 \large{A = 7 \\ B = 3 \\ C = 5}

@Steven Chase Hello somehow I have predicted your home location.
I just want know that is it correct or not??

Talulah Riley - 9 months, 2 weeks ago

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