Empty Set

Level pending

Consider two sets A = { ( x , y ) ∣ − 2 x − y = 2 } , B = { ( x , y ) ∣ ( c + 5 ) x + 3 y = 10 } . \begin{aligned} A &= \left \{ (x, y)\mid -2x-y=2 \right \}, \\ B &= \left \{ (x, y)\mid (c+5)x+3y=10 \right \}. \end{aligned} If A ∩ B = ∅ A \cap B=\emptyset , what is the value of the constant c ? c?

2 2 3 3 4 4 1 1

Ajay Dutta by Ajay Dutta , 24, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Addisu Mulugeta
Feb 10, 2014

First you assume as if you are going to solve simultaneous equation......so equate both the expression in set A and in set B...then to solve for x multiply the expression in set A by 3..and solve for x...you will obtain x=16/(c-1)....hence the solution is the set of all real numbers except c=1...meaning if c=1 the two sets have no elements in common...hence its solved

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...