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Kiran having some flowers to distribute among his 3 Frnds. He also have a bowl containing chemical. He gives some flowers to first frnd & deeps remaining in bowl, flowers get doubled. Then he give few flowers to another frnd. Again he deep remaining flowers in bowl, flowers again get doubled. He give all flowers to last frnd. All of 3 Frnds gets equal number of flowers. Then how many flowers Kiran had initially.
Note- multiple answers are possible.
The answer is 7.
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1 solution
Let n be the number of flowers he had originally. His first friend gets x flowers and every other friend gets x flowers. So he will have n-x flowers after his first friend, and 2(n-x) flowers after the chemical. Then he will have 2(n-x)-x after his second friend and 2(2(n-x)-x) after the chemical. Finally, after his third friend, he has none left therefore 2(2(n-x)-x)-x=0, which simplifies to 4n=7x. Now, he cant give a non whole number of flowers to his friends. And because 7 is prime, n=0 (mod 7) therefore n may be = to 7