Enough of Calculus

Calculus Level pending

A rope with its two ends held in place forms a curve called a catenary (assuming that the stiffness of the rope is negligible). A catenary takes the shape of the function: f ( x ) = a cosh ( x / a ) f(x) = a \cosh(x/a)

where cosh \cosh is the hyperbolic cosine function.

If a 50 foot rope hangs by its ends from two flagpoles, one 50 feet tall and one 40 feet tall, and at its lowest point is 20 feet above the ground, how far apart are the flagpoles?


The answer is 0.

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1 solution

Danish Ahmed
Jan 25, 2016

Ans : 0 \boxed{0} . They are right next to each other. The rope is simply doubled up on itself. No calculus required!

(It takes 30 30 feet of rope to reach from the 50 50 foot top of pole 1 to the low point of 20 20 feet. The remaining 20 20 feet are needed to go back up to the 40 40 foot elevation of pole 2.)

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