Enriching uranium with a mass spectrometer

A rudimentary way to enrich uranium for use in nuclear energy or weaponry is to pass an ionized beam of vaporized uranium through a modified mass spectrometer known as a calutron . Assuming an electronmagnet that produces a magnetic field of magnitude B = 1 T B = 1\text{ T} and a voltage oven rated at a potential difference of V = 2 kV V = 2\text{ kV} are available, what is the radius of the path traveled by the uranium-235 being isolated? Assume the beam of vaporized uranium is ionized to a charge of q = 1.6 × 1 0 19 C . q = 1.6\times10^{-19}\text{C}.

1 mm 1\text{ mm} 10 cm 10\text{ cm} 10 m 10\text{ m} 1 km 1 \text{ km}

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1 solution

July Thomas
May 6, 2016

Relevant wiki: Lorentz Force Law (Magnetic and Mixed Fields)

The radius of orbit for a particle in a uniform magnetic field is r = m v q B . r=\frac{mv}{qB}.

The only quantity missing is v . v. As the particle in a mass spectrometer gains its velocity by passing through the potential difference, use conservation of energy to find an expression of v v in terms of the known quantities.

q Δ V = Δ K q\Delta V = \Delta K q Δ V = 1 2 m v 2 q\Delta V = \frac12mv^2 v = 2 q Δ V m v=\sqrt{\frac{2q\Delta V}{m}}

Substitute this into the radius equation above.

r = m q B 2 q Δ V m = 1 B 2 m Δ V q 10 cm r = \frac{m}{qB}\sqrt{\frac{2q\Delta V}{m}} = \frac{1}{B}\sqrt{\frac{2m\Delta V}{q}} \approx 10\text{ cm}

Thanks for making this question, I really appreciate it. Just wanted to say that it says nitrogen in the last sentence of the problem which might confuse people a little because I think you mean uranium. Thanks again

Jacob Grays - 3 years, 2 months ago

Thanks for your answer I too got confused with the nitrogen in the last sentence, but you cleared it

Tecno Whizz - 1 year, 1 month ago

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