Sharing Candy Fairly

For the end-of-year examinations, Stella wants to bring a bag of candies to share with every student who earns an "A" in her class.

She knows that if there are 2, 3, 4, 5, 6, or even 7 top students, then she should be able to distribute the candies out evenly, and she doesn't want to take any candies home with her.

Given that she is going to bring at least 10 candies, what is the minimum number that she must bring?


The answer is 420.

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54 solutions

Naveena M
Jan 16, 2014

The total number of candies she brings should be divisible by 2,3,4,5,6 and 7. Hence, the minimum number of candies that she should bring is the LCM of those numbers, which is 420.

Just find the LCM. That's how I did it

Amartya Anshuman - 7 years, 4 months ago

To elaborate a little bit, consider the following: If a number is divisible by 4, it is also divisible by 2. If it is divisible by 3 and 2, it is divisible by 6. So that means that putting a 6 and putting a 4 are repetitive for when you multiply them all together. Multiplying 3 times 4 times 5 times 7 is 420, the answer.

Finn Hulse - 7 years, 4 months ago

I calculated a precise number of 420 candies but i was a bit nervous whether the answer would make sense, so i later figured out that my calculations were correct all along :) Hopefully

Valentin Stoykov - 7 years, 4 months ago

2×3=6 2×2=4 Hence the minimum number must be the product of its indivisible factors I.e. 2×5×6×7=420 Does that make sense?

Justin Sim - 7 years, 4 months ago

Lowestor least Common Multiple, the key to success

Vishal Barman - 6 years, 10 months ago

she should distribute the candies evenly to all right . so suppose there are 4 top students then if u consider 420 candies then each student gets 105 candies which is an odd number right . so right option should be 840

Santhosh Kumar - 7 years, 4 months ago

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here " evenly " means equally, not odd or even

pulkit kogta - 7 years, 4 months ago

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ohh . okay thank you .. :)

Santhosh Kumar - 7 years, 4 months ago

simply find the L.C.M OF 2,3,4,5,6,7 AND GET THE ansr...

suyash singh - 7 years, 2 months ago

can you send me your solution brifely

saba munawar - 7 years, 3 months ago

Why not 210 as 210 is divisible by all i.e 2,3,4,5,6, and 7 and LCM of them is 210 not 420

J C Sarkar - 7 years, 4 months ago

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it is not divisible by 4!!!!!!!!!!

Akanksha Yadu - 7 years, 3 months ago

210 is not divisible by 4.

Shashank Rammoorthy - 7 years, 4 months ago

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Right, answer should be 420

J C Sarkar - 7 years, 4 months ago
Raghav Dua
Jan 17, 2014

Take the lowest common multiple of 2, 3, 4, 5, 6 and 7

  =2, 3, 4, 5, 6, 7

(2) = 1, 3, 2, 5, 3, 7

(2) = 1, 3, 1, 5, 3, 7

(3) = 1, 1, 1, 5, 1, 7

(5) = 1, 1, 1, 1, 1, 7

(7) = 1, 1, 1, 1, 1, 1

Thus, LCM = 2 x 2 x 3 x 5 x 7 = 420. This is the least number of candies she must bring

210 is possible

Carlo Bentlage - 3 years, 2 months ago

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210 is divisible by all the other factors EXCEPT for 4. So if there were 4 students with A's, then it would not distribute evenly.

Emily Peng - 1 year, 7 months ago
Dheeraj Choudhary
Jan 17, 2014

to distribute candies evenly if there are 2, 3, 4, 5, 6, or even 7 top students.let the number of candies be n then n should be divisible by 2, 3, 4, 5, 6, and 7 together.

1) a number is divisible by 5 if we have 0 or 5 in last place

2) a number is divisible by 4 if last two digits of number is divisible by 4 and of-course number should be even

so from conditions 1) and 2) last digit should be 0 only. ( because if last digit is 5 it will not be divisible by even numbers 2,4 and 6)

also if a number is divisible by 6 it must be divisible by 2 and 3

so now minimum requirements are last place of number is 0 and it should be divisible by both 6 and 7 i.e. (6*7=42) so the least number comes is 420 which is divisible by 2, 3, 4, 5, 6, and 7 together.

number is 420

Just finding the common factor 2x2x3x5x7=420

Bhavesh Vora
Jan 16, 2014

LCM of 2,3,4,5,6,7 will come to 420

Shaun Loong
Jan 16, 2014

Since the number of candies can be divided equally among 2, 3, 4, 5, 6 and 7 people, then the least number of candies required is the lowest common multiple of 2, 3, 4, 5, 6 and 7.

Using algorithm method, I know that the LCM of 2, 3, 4, 5, 6, and 7 is 420 .

coorect

Zafar Ullah Khan - 7 years, 4 months ago
Long Plays
Mar 12, 2018

Thus she has to bring at least 420 candies.

David Mcsin
Jul 2, 2016

420 These are not candies but weed...

Wilson Widyadhana
Sep 14, 2015

The LCM of {2,3,4,5,6,7}= 420

SIMPLY LCM!!!

Tirthankar Ghosh
Mar 31, 2014

Find the LCM of 2,3,4,5,6 and 7.

the least number must be divisible by 2,3,4,5,6,7 and the number is 420.

Nishant Goel
Mar 21, 2014

LCM of 2,3,4,5,6,7 is 420

Smriti Prakash
Mar 2, 2014

The LCM of the number is required because only 420 candies can be shared equally among 2,3,4,5,6and7 toppers.

Akhil Boby
Mar 1, 2014

I just can't find the logic of one bringing 420 candies...God! To find the answer,you just have to find the LCM of the numbers which is 420.

Mohammad Fiyaz
Feb 26, 2014

minimum number of candies she must bring is 420.

because 420 is lowest common number that can be divided evenly if there are 2,3,4,5,6,7 top students.

420 is LCM of 2,3,4,5,6,7.

Ketan J
Feb 26, 2014

find the lcm of the given numbers and that will give you the anser

Saubia Ansari
Feb 24, 2014

Just find the LCM of the numbers 2,3,4,5,6and7=420 and that's the answer

Wil Medeiros
Feb 21, 2014

The number of candies must be divisible by all n n in the set of integers from 2 to 7. The smallest number which satisfies this condition is l c m ( 2 , 3 , 4 , 5 , 6 , 7 ) lcm(2,3,4,5,6,7) , which is equivalent to 2 2 × 3 × 5 × 7 = 420 . 2 ^2 \times 3 \times 5 \times 7 = \boxed{420}.

Aditya Joshi
Feb 17, 2014

If she brings x x candies, x x should be divisible by 2 , 3 , 4 , 5 , 6 2,3,4,5,6 and 7 7 to be sure that the candies are equally distributable. Now, the minimum number that is divisible by 2 , 3 , 4 , 5 , 6 , 7 2,3,4,5,6,7 is just l c m ( 2 , 3 , 4 , 5 , 6 , 7 ) = 420 lcm(2,3,4,5,6,7) = \boxed{420}

Rizwan Khawaja
Feb 17, 2014

2, 3, 4, 5, 6, 7 = 2, 3, 2x2, 5, 2x3, 7 and common multiples = 2x3x2x5x7 = 420 Answer

Mashoodha P V
Feb 15, 2014

LCM

Shahzad Rafique
Feb 13, 2014

simply get LCM of 2,3,4,5,6,7 which is 420

Samuel Squigi
Feb 9, 2014

Use the Ladder method, put 2,3,4,5,6,7 and then factorise to get 2^2x3x5x7 as your LCM. Therefore you get 420 which, incidentally, is 420YOLO!!!! (just saying)

lol, squigi boo

Victor Loh - 7 years, 4 months ago
Aakansha Dey
Feb 8, 2014

L.C.M of 2,3,4,5,,6,7 = 420

unable to understand the question properly. pls help...

shivani sinha - 7 years, 3 months ago

It is a very simple problem. Find the Lowest Common Multiple of the numbers Therefore, LCM {2,3,4,5,6,7}=LCM{4,5,6} * 7 Thus, the LCM= the answer=420

The minimum number of candies she should bring is 420.

Sidhi Kharkia
Feb 5, 2014

taking L.C.M of 2,3,4,5,6, and 7;

we get 420.

Therefore, Stella must bring 420 candies to distribute it out evenly.

Dilbwag Singh
Feb 4, 2014

As written in the question there can be 2, 3, 4, 5, 6, or even 7 top students. So the answer is the L.C.M of the numbers 2,3, 4, 5, 6, 7 which is 420

Bestin Thomas
Feb 3, 2014

find the LCM of the numbers

Vivek Maurya
Feb 1, 2014

She has to bring multiples of all number of students(2, 3, 4, 5, 6,7) to distribute candies equally. so find the LCM of 2, 3, 4, 5, 6,7 , which is 420.

Jeffin John
Jan 31, 2014

the ans must be a multiple of 2,3,4,5,6,7

Just simply get the GCF of 2,3,4,5,6 and 7

so the their GCF is 420

oh sorry its LCM

Jireh Emmanuel Gumaro - 7 years, 4 months ago
Kiruba Shankar K
Jan 29, 2014

For such a kind of problems, find the LCM. And that would be the minimum number needed.

Anish Mukherjee
Jan 28, 2014

We just need to find the L.C.M of the given numbers ie.420 . That is our answer !!

The minimum number which can be divided equally among 2or3or4or5or6or7 students is the LCM of all those numbers

LCM of 2,3,4,5,6,7 is 420

Srikanth Kummara
Jan 24, 2014

lcm of all the numbers

Abhishek Gupta
Jan 24, 2014

She should be able to candies evenly to 2,3,4,5,6 or 7 students, which means we have to find the least no. divisible by 2.3.4.5.6 and 7 which is their L.C.M - 420

Pulkit Kogta
Jan 22, 2014

find the LCM of 2,3,4,5,6,7= 420

Manan Gupta
Jan 22, 2014

Taken LCM of 2,3,4,5,6,7

Syed Zayed
Jan 21, 2014

I took 2 values like 5 & 6 into consideration. Then multiply them, got 30. Then incremented it by 30 like 30,60,90... and thus found the required value/number.

Engma Dp
Jan 20, 2014

As it clear that she wont take back any candies if there are 2,3 , 4, 5, 6 or even 7 students who top, it is evident that number of candies that she get is Lowest Common Multiple of 2,3,4,5, 6,7 which is 420 .

Tarun Arora
Jan 20, 2014

LCM - Lowest Common Multiple

Sunil Pradhan
Jan 19, 2014

Number is LCM of 2, 3, 4, 5, 6, 7 = 420

Indranil Ghosh
Jan 19, 2014

simply LCM

Nitish Dubey
Jan 18, 2014
  • The number should be perfectly divisible by 2,3,4,5,6,7,with any number i.e,quotient (no.of candies to each).
  • and it should be the first or minimum no. to be divided.
  • Hence,L.C.M will provide the required no. .
  • L.C.M{2,3,4,5,6,7}= 420 .
Muhammad Usman
Jan 18, 2014

lcm is the answer

Manash P
Jan 18, 2014

Simply least common multiple of all numbers

1/2 + 1/3 = 4/6 (take only the value of the denominator) 1/6 + 1/4 = 5/12 (same we did at the first) the idea is to get only the common multiple disregarding the numerator 1/12 + 1/5 = 17/60 do this in repetition until 1/7 1/60 + 1/6 = 11/60 1/60 + 1/7 = 67/420 (420) isolating the denominator we have the least common multiple of every number

*isolating the denominator we have the product of the LCM of each number

van joshua abergos - 7 years, 4 months ago
Dhiraj Agarwalla
Jan 18, 2014

For Stella to distribute candies among the students evenly , the number of candies should be divisible by the number o toppers. So the solution will be H.C.F of the number of expected toppers. The H.C.F of 2,3,4,5,6,7 is 420

Peter Michael
Jan 17, 2014

This requires the lowest common multiple of the possible number of students. LCM(2,3,4,5,6,7)=420

Ankit Goyal
Jan 17, 2014

Find LCM of 2, 3, 4, 5, 6 and 7 = 420

Given problem amounts to LCM(2,3,4,5,6,7) LCM(2,3,4,6)=12 LCM(5,7,12)=5x7x12=420 420 is the answer

Siddharth Kothari
Jan 17, 2014

We know that we can evenly distribute between 2,3,4,5,6,7 kids equally. Hence the number should be divisible by them. We need to find the minimum number so we took Least Common Multiple of 2,3,4,5,6,7 which gave us 420.

Abhilash Goyal
Jan 16, 2014

Just find their LCM ...

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