Equatioñ

Algebra Level 3

If coefficients of biquadratic equation are all distinct and belong to the set { 9 , 5 , 3 , 4 , 7 } \{-9,-5,3,4,7\} , then equation has:

None of these choices 4 real roots, 2 are conjugate surds & other 2 are also conjugate surds 4 imaginary roots At least 2 real roots

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Vedant Sharda
Jan 16, 2016

Let a biquadratic equation f(x)= ax⁴+bx³+cx²+dx+e

Then a+b+c+d+e = -9-5+3+4+7 = 0

So, at x= 1, f(x) = 0 (1 real root) remaining 3 cannot be imaginary so at least 2 real root

I don't understand your question and solution.

A biquadratic equations is a quartic equation having no odd powers.

Pi Han Goh - 5 years, 4 months ago

How remaining two cannot be imaginary ?

Ramendra Polai - 5 years, 4 months ago

Log in to reply

Remaining 3 cannot be imaginary as imaginary roots occur in conjugate pair

so atleast 2 real root

Vedant Sharda - 5 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...