Equidistantiation

Geometry Level 3

True or False : In 2D space, there exists 4 points equidistant with one another.

True False

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Efren Medallo
Sep 25, 2016

In 2D space, there can only be at most 3 points which can be made to be equidistant with one another.

This can be verified by drawing a circle with fixed radius r r on any chosen center. Along its circumference, choose the second point, and draw a circle with the same radius. From there you will have two intersection points, both equidistant from the two chosen points (with distance r r ), but whose distance to the other intersection is not the same as the radius.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...