Let hexagon on the cartesian plane be convex and equilateral with opposite sides parallel. Furthermore, let be the origin, let have coordinates , and let . Given that the -coordinates of the vertices of this hexagon are distinct elements from the set , the area of the hexagon can be expressed as , where and are positive integers and is square-free. What is ?
Details and Assumptions
Don't be fooled. The biconditionality of equilaterality and equiangularity only holds for triangles. In other words, equilaterality implies equiangularity (and vice versa) is only true when the figure is a triangle.
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