Equilateral Spring Triangle

Level 2

Three point masses m m are attached together by identical springs. When placed at rest on a horizontal surface the masses form a triangle with side length l l . When the assembly is rotated about its center at angular velocity ω \omega , the masses form a triangle with side length 2 l 2l . What is k m ω 2 \dfrac{k}{m\omega^2} for the springs, if k k is the spring constant?

Note : A version of this problem appeared on the 2012 F = ma exam.

2 3 \dfrac{2}{3} 1 3 \dfrac {1}{3} 1 3 \dfrac{1}{\sqrt{3}} 2 3 \dfrac{2}{\sqrt{3}}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...