Equilateral Triangle Dissection

Geometry Level 5

An equilateral triangle

has an interior point P P from which the distances to the 3 3 vertices are distinct integers a b c a a\neq b\neq c\neq a that satisfy the condition

2 Δ x x x = Δ a a a + Δ b b b + Δ c c c + 3 Δ a b c 2\Delta xxx=\Delta aaa+\Delta bbb+\Delta ccc+3\Delta abc

where the notation Δ a b c \Delta abc shall denote the non-zero area of a triangle with sides a , b , c a, b, c , and x x is the side of the equilateral triangle.

Find the minimum value a + b + c a+b+c can have.


The answer is 9.

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1 solution

Michael Mendrin
Jul 20, 2014

For any P P this condition

2 Δ x x x = Δ a a a + Δ b b b + Δ c c c + 3 Δ a b c 2\Delta xxx=\Delta aaa+\Delta bbb+\Delta ccc+3\Delta abc

is always true, because it's a geometrical identity. Hence, we examine the first few possible sets

{ 1 , 2 , 3 } , { 1 , 2 , 4 } , { 1 , 2 , 5 } , { 1 , 3 , 4 } , { 2 , 3 , 4 } \{ 1,2,3\} ,\{ 1,2,4\} ,\{ 1,2,5\} ,\{ 1,3,4\} ,\{ 2,3,4\}

and then rule out
{ 1 , 2 , 3 } \{ 1,2,3\} because the point P P is outside the equilateral triangle
{ 1 , 2 , 4 } , { 1 , 2 , 5 } \{ 1,2,4\} ,\{ 1,2,5\} because no point P P is possible with those distances
{ 1 , 3 , 4 } \{ 1,3,4\} because Δ 134 \Delta 134 is zero, leaving
2 + 3 + 4 = 9 2+3+4=9 as the smallest possible answer meeting all conditions.
The figure for this answer is already given at the start of this problem.


Proof of this geometrical identity can be found through dissections. The following graphic suggests how this may be done.

Sir I want to ask that the minimum value of a + b + c a+b+c depends on the value of x x or not.

Purushottam Abhisheikh - 6 years, 4 months ago

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