Equilibrium-2

Chemistry Level 3

At temperature T = 1 3 R T=\dfrac{1}{3R} , Find the equilibrium constant in terms of partial pressure K p K_{p} for the following reaction if value of K c = 2 12 × 3 19 × 5 16 K_{c}=2^{12} \times 3^{19} \times 5^{16} after balancing the equation and getting the values of m , n , h , j m,n,h,j which all are integers.

m C 6 H 14 ( g ) + n O 2 ( g ) h C O 2 ( g ) + j H 2 O ( l ) \large{mC_{6}H_{14}(g) + nO_{2}(g) \rightleftharpoons hCO_{2}(g) + jH_{2}O(l)}

Balance the following reaction. Now find the value of K p K_{p}

If K p = 2 a × 3 b 5 c K_{p}=\dfrac{2^a \times 3^b}{5^c} . Find the value a + b + c a+b+c .

Assumption

  • Here R is gas constant.

  • Here T is in Kelvin

ORIGINAL


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The answer is 24.

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1 solution

Suhas Sheikh
Jun 16, 2018

A=12,B=28,C=-16

Yes this is correct, but shouldn't you explain how you arrived at the answer????

Aaghaz Mahajan - 2 years, 3 months ago

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