Equilibrium everywhere

A uniform rod of length $L$ is in vertical plane with upper end resting against a smooth vertical wall $OY$ ( $O$ being origin) and lower end resting on smooth surface $OC$ which is perpendicular to the plane of the figure. Rod is in equilibrium for any position. If the equation of the curve $OC$ is $x^2+\omega y^2 + kLy =0$ . Find $\omega^2-k^2$ +4.