A and B in the above combination of resistors.
Find the equivalent resistance between the two points
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The circuit will have following configurations:
One resistance of 2R is in parallel.
One resistance of R in parallel connected to two parallel resistors of 2R (R+R) and 2R.
Thus the resultant resistance will be the reciprocal of
2 R 1 + { R + ( 2 R + 2 R 2 R x 2 R ) 1 } = 2 R 1 + 2 R 1 = R 1 .
The reciprocal of 1/R is the resultant resistance of the circuit which is R.
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The equivalent resistance
R e q = 2 R / / [ R + 2 R / / ( R + R ) ]
= 2 R / / ( R + 2 R / / 2 R )
= 2 R / / ( R + 2 R + 2 R 2 R × 2 R )
= 2 R / / ( R + R )
= 2 R / / 2 R
= R Ω