Equivalent Weight

Chemistry Level 4

What is the equivalent weight of H N O X 3 \ce {HNO3} in the reaction -

Cu reacting with H N O X 3 \ce {HNO3} forming C u (NO3) X 2 \ce {Cu{(NO3)}_{2}} and NO and water

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The answer is 84.

Aniket Sanghi by Aniket Sanghi , 21, India

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1 solution

In the balanced equation, the stiochometric coefficients of nitric acid and copper are 8 8 and 3 3 respectively. Let M M denote the molecular mass of nitric acid. Then, Equivalent mass of nitric acid = M change in ON per molecule of nitric acid = 8 M change in ON in Cu in balanced equation = 8 M 6 = 84 \text{Equivalent mass of nitric acid }=\frac{M}{\text{change in ON per molecule of nitric acid}}\\=\frac{8M}{\text{change in ON in Cu in balanced equation}}\\=\frac{8M}{6}\\=84

6 Helpful 0 Interesting 0 Brilliant 0 Confused

@neelesh vij This is no execption. It's just a consequence of definition.

A Former Brilliant Member - 5 years, 1 month ago

Right! Nice one!

Aniket Sanghi - 5 years, 1 month ago

@Deeparaj Bhat can you please explain why the change in oxidation number 6?

shivam mishra - 5 years ago

Here The n-factor being inversely proportional to stochiometric coefficient Fact is being nicely used :)

Suhas Sheikh - 3 years ago

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