Euler Would Love This One

Algebra Level 3

e 2 x + 2 e x + 1 = 0 \large{e^{2x}+2e^{x}+1=0} Solve the above equation for x x .

Note: i = 1 i = \sqrt{-1}

i π ( 2 n + 1 ) i \pi (2n+1) 1 i π n i \pi n ln ( 2 ) \ln(2)

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1 solution

Kay Xspre
Nov 30, 2015

We factorize it into ( e x + 1 ) 2 = 0 (e^x+1)^2 = 0 . By Euler's identity, e i π + 1 = 0 e^{i\pi}+1 = 0 , so we can conclude that i π i\pi is an answer. Put it into generalized form where n n is an integer gives i π + i 2 n π = i π ( 2 n + 1 ) i\pi+i2n\pi = i\pi(2n+1)

Shoot dumb me forgot the generalized form

Mardokay Mosazghi - 5 years, 5 months ago

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