Evaluate
2 × 3 × 4 ( 1 + 2 + 3 ) × ( 3 + 4 + 5 ) × ( 5 + 6 + 7 ) .
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Temos que 1 + 2 + 3 = 6 , 3 + 4 + 5 = 1 2 e 5 + 6 + 7 = 1 8 , e no denominador 2 × 3 × 4 = 6 × 4 , e ai. tem-se que o resultado vem de 6 × 4 6 × 1 2 × 1 8 = 3 × 1 8 = 5 4 .
(1+2+3)=(6)×(3+4+5)=(12)×(5+6+7)=(18) now we take multiple valeus 6×12×18=1296/2×3×4 1296/24=54.
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Given Equation: (1+2+3)×(3+4+5)×(5+6+7) / 2×3×4
Use order of operations for numerator and denominator by adding together what's inside the parenthesis first: (1+2+3) = 6, (3+4+5) = 12, (5+6+7) = 18
Now we would re-write the problem: (6) x (12) x (18) - You can take the parenthesis out if you'd like at this point.
6 x 12 x 18 = 1296
Our new equation would now look like: 1296 / 2 x 3 x 4 OR 1296 / 24
Divide 24 into 1296 to get: 54