Evaluate a limit

Calculus Level 2

Find lim n ζ ( n ) \displaystyle \lim_{n \rightarrow \infty} \zeta (n)

where ζ ( x ) \zeta (x) represents the zeta function .


The answer is 1.00.

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2 solutions

Aditya Kumar
Feb 15, 2016

It is quite simple.

lim s ζ ( s ) = lim s n = 1 1 n s \displaystyle \lim _{ s\rightarrow \infty }{ \zeta \left( s \right) } =\lim _{ s\rightarrow \infty }{ \sum _{ n=1 }^{ \infty }{ \frac { 1 }{ { n }^{ s } } } }

lim s ζ ( s ) = lim s 1 1 s + 1 2 s + 1 3 s + . . . \lim _{ s\rightarrow \infty }{ \zeta \left( s \right) } =\quad \lim _{ s\rightarrow \infty }{ \frac { 1 }{ { 1 }^{ s } } +\frac { 1 }{ { 2 }^{ s } } +\frac { 1 }{ { 3 }^{ s } } +... }

lim s ζ ( s ) = 1 + 0 + 0 + 0 + . . . = 1 \lim _{ s\rightarrow \infty }{ \zeta \left( s \right) } =\quad 1+0+0+0+...=1

Easy and cute. (Seemed hard at first sight :P )

Nihar Mahajan - 5 years, 4 months ago
Harsh Shrivastava
Feb 15, 2016

Pretty ONE huh?

You don't need WA for this.

Aditya Kumar - 5 years, 4 months ago

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I know but to show people that ζ ( 10000 ) \zeta (10000) is really close to 1,I added the value of zeta(10000) in my solution.

Harsh Shrivastava - 5 years, 4 months ago

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