Evaluate composite functions

Algebra Level 2

If f ( a ) = a f(a)=\sqrt a and ​​ g ( b ) = 1 b g(b)= \dfrac{1}{b} , what is g f ( 0.64 ) = ? g\circ f(0.64) = \ ?


The answer is 1.25.

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2 solutions

Chew-Seong Cheong
Sep 11, 2017

g f ( 0.64 ) = g ( f ( 0.64 ) ) = g ( 0.64 ) = g ( 0.8 ) = 1 0.8 = 1.25 \begin{aligned} g \circ f(0.64) & = g(f({\color{#3D99F6}0.64})) = g\left(\sqrt{\color{#3D99F6}0.64}\right) = g({\color{#D61F06}0.8}) = \frac 1{\color{#D61F06}0.8} = \boxed{1.25} \end{aligned}

Nazmus Sakib
Sep 11, 2017

Let's evaluate f ( 0.64 ) f(0.64)

f ( a ) = a f(a)=√a

f ( 0.64 ) = 0.64 f(0.64)=√0.64

= 64 100 \dfrac{√64}{√100}

= 8 10 \dfrac{8}{10}

= 4 5 \dfrac{4}{5}

we know that g ( f ( 0.64 ) g(f(0.64) ) is the same as

g ( 4 5 ) g(\dfrac{4}{5}) because f ( 0.64 ) f(0.64) = 4 5 \dfrac{4}{5}

so now let's evaluate g ( 4 5 ) g(\dfrac{4}{5})

g ( b ) g(b) = 1 b \dfrac{1}{b}

g ( 4 5 ) g(\frac{4}{5}) = 5 4 \dfrac{5}{4}

so, ( g o f ) ( 0.64 ) (gof)(0.64) = 5 4 \dfrac{5}{4}

or, \color\red{1.25}

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