If x = 1 0 2 − 1 0 , what is the value of 1 − 1 0 x x 2 ?
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nice solution
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great solution
wow the thing i did is because theirs a square i cancelled the square root haha silly me
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nice solution
Given is x=\sqrt{102} - 10 Rearrange it as folowed x+10=\sqrt{102}
Squaring both sides x^2 + 2(10)(x) + 100 = 102
x^2 + 20x = 102-100 x^2 + 20x = 2
So
x^2 = 2 - 20x or x^2 = 2(1 - 10x)
Now substitute the value of x^2 in the fraction. frac {x^2}{1 - 10x}
= frac { 2(1 - 10x)}{1 - 10x} = 2
good
i was just solving it bt i lost it damn
x = (sqrt(102)-10)^2/(1-10(sqrt(102)-10)) note: sqrt(102) = 10.09950494
therefore, x = 2
square root of 102 - 10 squared = 102-100 so the answer will be 2
1-10 (square root of 102 - 10)
multiply the number 10 .. 10x10 = 100.. then solve the close parenthesis (102-100) = 2
2 over 1-2 = 2 over 1 then i solve it 2/1 is 2
sorry for my solution .. i dont know how to explain but im so interested for solving this kind of problem.. xD hope u understand i love math :D
x^2 / (1-10x) = (V102 - 10)^2 / [1-10(V102 - 10)] = 202 - 20V102 / 101 - 10V102 = 2
rearanging we get (x+10)^2=102 x^2+20x+100=102 x^2=2-20x x^2=2(1-10x)
hence given exprsn =2
x=sqrt(102)-10;
((sqrt(102)-10)^3)/(1-10(sqrt(102)-10)) =(102-20 sqrt(102)+100)/(1-10sqrt(102)+100) =(202-20 sqrt(102))/(101-10sqrt(102)) =(2(101-10sqrt(102))/(101-10sqrt(102)) =2
nice...
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Substitute x = 1 0 2 − 1 0 into 1 − 1 0 x x 2
⟹ 1 − 1 0 ( 1 0 2 − 1 0 ) ( 1 0 2 − 1 0 ) 2
⟹ 1 − 1 0 1 0 2 + 1 0 0 1 0 2 − 2 0 1 0 2 + 1 0 0
⟹ 1 0 1 − 1 0 1 0 2 2 0 2 − 2 0 1 0 2
⟹ 1 0 1 − 1 0 1 0 2 2 ( 1 0 1 − 1 0 1 0 2 )
⟹ 2