Evaluate the function provided by the infinite product at an argument of pi/3.

Calculus Level pending

( x n = 1 ( 1 4 x 2 π 2 ( 2 n 1 ) 2 ) ) ( π 3 ) \left(x\to\prod _{n=1}^{\infty } \left(1-\frac{4 x^2}{\pi ^2 (2 n-1)^2}\right)\right)\left(\frac{\pi }{3}\right)

Amplification: ( x n = 1 ( 1 4 x 2 π 2 ( 2 n 1 ) 2 ) ) \left(x\to\prod _{n=1}^{\infty } \left(1-\frac{4 x^2}{\pi ^2 (2 n-1)^2}\right)\right) is a nameless function of x x , to which an argument of ( π 3 ) \left(\frac{\pi }{3}\right) is given. Part of the problem is determining what that function actually is.


The answer is 0.5.

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1 solution

The infinite product evaluates to cos ( x ) \cos(x) . cos ( π 3 ) = 1 2 \cos(\frac{\pi}{3})=\frac12 .

it was a really easy problem

Nahom Assefa - 2 years ago

Thank you.

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