( x → n = 1 ∏ ∞ ( 1 − π 2 ( 2 n − 1 ) 2 4 x 2 ) ) ( 3 π )
Amplification: ( x → ∏ n = 1 ∞ ( 1 − π 2 ( 2 n − 1 ) 2 4 x 2 ) ) is a nameless function of x , to which an argument of ( 3 π ) is given. Part of the problem is determining what that function actually is.
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The infinite product evaluates to cos ( x ) . cos ( 3 π ) = 2 1 .