Evaluating the rate law expression

Chemistry Level 2

A B C D

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1 solution

Abhishek Singh
Nov 18, 2014

Let us divide the data into four cases C a s e I , I I , I I I , I V \mathcal{Case I,II,III,IV} respectively. From our reference to C a s e I a n d I I \displaystyle{\mathcal{Case I and II}} on doubling the concentration of B \displaystyle{B} the rate doubles so we can see that it is of order 1 \displaystyle{1} w.r.t. B \displaystyle{B} and on halving the concentration of A \displaystyle{A} the rate too decreases to half. Again on doubling the concentration of both A \displaystyle{A} and B \displaystyle{B} the rate quadruples .Hence our rate law is R a t e = k [ A ] 1 [ B ] 1 \boxed{\mathcal{Rate} = k[A]^{1} [B]^{1} }

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