Even! Evenly divisible upon prime

$N = \dfrac{10!}{11}\qquad \overline{N} = \dfrac{10!-M}{11}$ The number $(N)$ above doesn't leave remainder 0. However, $\overline{N}$ leaves 0 remainder when $M$ is subtracted from $10!$ . Find the largest possible value of $M<10!$ .

Bonus (if interested): Find the total such $M$ such that $\overline{N}$ is evenly divisible by 11.