Even integers

The sequence of numbers forms an arithmetic progression. The common difference is $2$ ; number of terms is $4139$ ; and the sum is of the terms is $17135460$ . We can use the formula:

$s=\dfrac{n}{2}(a_1+a_n)$ where: $s=sum$ , $n=number~of~terms$ , $a_1=first~term$ and $a_n=n^{th}~term$

Substituting, we get

$17135460=\dfrac{4139}{2}(a_1+a_{4139})$

$\dfrac{17135460(2)}{4139}=a_1+a_{4139}$

$a_1+a_{4139}=$ $\boxed{8280}$ $\color{#D61F06}\boxed{\text{answer}}$